【头歌-Python】Python第六章作业
洛水入长安 2024-06-19 11:05:03 阅读 73
第1关:列表的属性与方法
a = int(input())ls = []for i in range(a): t = input().split(" ") if t[0] == 'insert': ls.insert(int(t[1]), int(t[2])) elif t[0] == 'print': print(ls) elif t[0] == 'remove': ls.remove(int(t[1])) elif t[0] == 'append': ls.append(int(t[1])) elif t[0] == 'sort': ls.sort() elif t[0] == 'pop': ls.pop() elif t[0] == 'reverse': ls.reverse()
第2关:推导式与生成器
ls = ['the lord of the rings', 'anaconda', 'legally blonde', 'gone with the wind']s = input() if s == '1': print([x ** 3 for x in range(10)])elif s == '2': print([x ** 3 for x in [0, 2, 4, 6, 8]])elif s == '3': print([(x, x ** 3) for x in [1, 3, 5, 7, 9]])elif s == '4': for i in range(4): ls[i] = ls[i].capitalize() print(ls)else: print('结束程序')
第3关:列表的合并与排序
list1 = list(map(int,input().split()))list2 = list(map(int,input().split()))for i in list2: list1.append(i)list1.sort(reverse=True)print(list1)
第4关:二维列表排序
a = int(input())b = int(input())list1 = [('dungeon',7),('winterfell',4),('bran',9),('meelo',6)]list2 = [[ 'Angle', '0121701100106',99], [ 'Jack', '0121701100107',86], [ 'Tom', '0121701100109',65], [ 'Smith', '0121701100111', 100], ['Bob', '0121701100115',77], ['Lily', '0121701100117', 59]]if a>=len(list1): print(sorted(list1,key = lambda x:x[1]))else: print(sorted(list1,key = lambda x:x[1])[0:a])if b>=len(list2): print(sorted(list2,key = lambda x:x[0])) print(sorted(list2,key = lambda x:x[2]))else: print(sorted(list2,key = lambda x:x[0])[0:b]) print(sorted(list2,key = lambda x:x[2])[0:b])
第5关:动物重量排序
ls = []while True: temp = input() if temp == '': break ls.append(temp.split()) print(sorted(ls,key=lambda x:float(x[1][:-1]) * 1000 if x[1][-1] == 't' else float(x[1][:-2])))
第6关:身份证号升位
a = input()if (int(a[6]) == 0 and int(a[7]) >= 5) or int(a[6]) > 0: str = a[:6] + '19' + a[6:]else: str = a[:6] + '20' + a[6:]sum = (int(str[0]) * 7 + int(str[1]) * 9 + int(str[2]) * 10 + int(str[3]) * 5 + int(str[4]) * 8 + int(str[5]) * 4 + int(str[6]) * 2 + int(str[7]) * 1 + int(str[8]) * 6 + int(str[9]) * 3 + int(str[10]) * 7 + int(str[11]) * 9 + int(str[12]) * 10 + int(str[13]) * 5 + int(str[14]) * 8 + int(str[15]) * 4 + int(str[16]) * 2) % 11if sum == 0: str = str + '1'if sum == 1: str = str + '10'if sum == 2: str = str + 'X'if sum == 3: str = str + '9'if sum == 4: str = str + '8'if sum == 5: str = str + '7'if sum == 6: str = str + '6'if sum == 7: str = str + '5'if sum == 8: str = str + '4'if sum == 9: str = str + '3'if sum == 10: str = str + '2'print(str)
第7关:完美立方数
Cube = int(input())for i in range(2,Cube+1): for a in range(2,i+1): for b in range(a,i+1): for c in range(b,i+1): if pow(i,3)==pow(a,3)+pow(b,3)+pow(c,3): print('Cube = {},Triple = ({},{},{})'.format(i,a,b,c))
第8关:约瑟夫环问题
n, k = map(int, input().split(' '))ls = []if k < 2 or n < k or n<0 or k<0: print('Data Error!')else: for i in range(1, n + 1): ls.append(i) while len(ls) > k - 1: num = 1 for i in ls: if num == k: ls.pop(k-1) ls = ls[k-1:] + ls[:k-1] break num = num + 1 ls.sort() print(ls)
第9关:统计英文文件中的单词数
import stringdef read_file(file): """接收文件名为参数,读取文件中的数据到字符串中,返回这个字符串""" with open(file, 'r', encoding='utf-8') as f: data = f.read() return data def word_list(txt): """接收字符串为参数,用空格替换字符串中所有标点符号,根据空格将字符串切分为列表 返回值为元素为单词的列表""" for punctuation in string.punctuation: txt = txt.replace(punctuation, ' ') return txt.split()def number_of_words(ls): """接收一个以单词为元素的列表为参数,返回列表中单词数量,返回值为整型""" return len(ls)if __name__ == '__main__': filename = input() text = read_file('step10/'+filename) words_list = word_list(text) words_counts = number_of_words(words_list) print('共有{}个单词'.format(words_counts))
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